Question

a vehicle has 1000 kg mass and co efficient of friction between tyres and road is 0.4 what is the maximum breaking force (retarding force) which can stop the vehicle on road ?

Answer 1

When a vehicle has 1000 kg mass as well as co efficient of friction between tyres then the road is 0.4 then the maximum breaking force will be 4905 KN, this can stop the vehicle on road.

By assuming the acceleration as 0.54 (coz Friction is 0.4), the force = mass x acceleration = 1000 x 9810 x 0.5 = 4905 KN.