A vehicle has a mass of 1500 kg the vehicle is to be stop with the negative acceleration of 1.7 metre per second square the force of friction between the vehicle and road is
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F = ma
= 1500 kg × (-1.8 m/s²)
= -2700 N
(Here -ve sign indicates that it is friction)
Friction between vehicle and road is 2700 N (= 2.7 kN)
= 1500 kg × (-1.8 m/s²)
= -2700 N
(Here -ve sign indicates that it is friction)
Friction between vehicle and road is 2700 N (= 2.7 kN)
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➧ Mass 0f Vehicle ➾ 1500 N
➧ Acceleration ➾ -1.7 m/s²
➧ Force ➾ ?
❱ F ➾ m × a
F ➾ 1500 Kg (-1.7 m/s²)
F ➾ -2500 Kg m/s²
F ➾ -2500 N ...✔
_________ Thanks...✊
➧ Mass 0f Vehicle ➾ 1500 N
➧ Acceleration ➾ -1.7 m/s²
➧ Force ➾ ?
❱ F ➾ m × a
F ➾ 1500 Kg (-1.7 m/s²)
F ➾ -2500 Kg m/s²
F ➾ -2500 N ...✔
_________ Thanks...✊
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