Question

A vehicle mass of 10kg is moving with a velocity of 5ms. To stop it in 1/10th sec the required force in opposite direction is ​

Answer 1

Answer:

500 N

Explanation:

A vehicle mass of 10kg is moving with a velocity of 5ms. To stop it in 1/10th sec the required force in opposite direction is ​

Initial Velocity  = 5 m/s

Final Velocity = 0 m/s

Time = 1/10  sec

Using V = U + at

=> 0 = 5 + a(1/10)

=> a = -50 m/s²

Force Required in opposite direction = -ma

= -10 *(-50)

= 500 N

required force in opposite direction is ​ = 500 N

Answer 2

Answer:

500 N

Explanation:

A vehicle mass of 10kg is moving with a velocity of 5ms. To stop it in 1/10th sec the required force in opposite direction is ​

Initial Velocity  = 5 m/s

Final Velocity = 0 m/s

Time = 1/10  sec

Using V = U + at

=> 0 = 5 + a(1/10)

=> a = -50 m/s²

Force Required in opposite direction = -ma

= -10 *(-50)

= 500 N

required force in opposite direction is ​ = 500 N