A vehicle moves at a speed of 40km/h it is stopped by applying brakes which produces a uniform acceleration of -0.6m/s2 calculate the distance
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u = 40 km/h = 100/9 m/s
v =0
a = -0.6 m/s²
∴v²- u² = 2as
⇒(0)² - (100/9)² = 2×(-0.6)×s
⇒s = 10000/(81×1.2)
=102.9 m
v =0
a = -0.6 m/s²
∴v²- u² = 2as
⇒(0)² - (100/9)² = 2×(-0.6)×s
⇒s = 10000/(81×1.2)
=102.9 m
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