Question

a vehicle moving with a uniform acceleration of 2m/^2 has a velocity of 4m/s at a certain time. What will it's velocity be at: 1 second later?​

Answer 1

Answer:

The uniform acceleration = 2 m/s²

Velocity = 4 m/s

We need to find the velocity after 1 second.

Let us use the first equation of motion : v = u + at

⇒ v = 4 + 2*1

⇒ v = 4 + 2

⇒ v = 6 m/s

Hence, the velocity after 1 second = 6 m/s.

EXTRA INFORMATION -

• Avg. Speed = ∆x/∆t
• v = lim (∆t ➜ 0) ∆x/∆t = dx/dt
• Avg. acceleration = ∆v/∆t
• a = lim (∆t ➜ 0) ∆v/∆t = dv/dt
• ∆x = x_2 - x_1
• v = u + at
• v² - u² = 2as
• s = ut + ½at²

Answer 2

Given :-

• Acceleration Of Vehicle = 2m/s²

• Initial Velocity = 4m/s

• Time = 1 second.

To Find :-

• Final Velocity after 1 second.

Solution :-

We know the First Equation Of Motion,

v = u + at.

In this,

v stands for Final Velocity,

u stands for Initial Velocity,

a stands for Acceleration,

t stands for Time.

By Putting The Values, We Get,

v = 4 + 2 × 1.

➛v = 4 + 2.

➛v = 6m/s.

Hence, Velocity after 1 second = 6m/s.

3 Equations Of Motion :-

• v = u + at.
• v² - u² = 2as.
• s = ut + ½ at²