A vehicle moving with speed 30 km/h on a straight
road can be stopped in 6 m distance by applying
brakes. If same vehicle is moving with 60 km/h and
brakes provide double retardation then vehicle will
stop after travelling
Answers
Answered by
16
Answer:
12m
Explanation:
Given
u1 = 30km/h = 8.3 m/s
s1 = 6m
v1 = 0
v2 = 60 km/h = 16.6 m/s
a2 = 2a1
To Find:
s2
Solution
v² - u² = 2as
0²- (8.3)² = 2(-a) 6
69 = 12a
a = 5.75 m/s²
now
u = 16.6 m/s
v² - u² = 2as
0 - (16.6)² = 2(-2a)s
275.6 = 4(5.75)s
275.6 = 23s
s ≈ 12m
Answered by
0
Answer:
Answer=12m
Explanation:
the answer is 12 m.
Hope it helps!!!
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