Question

A vehicle of 100 kg is moving with a velocity of 5 m/sec. To
stop it in 1/10 sec , the required force in opposite direction is
​

Answer 1

Answer:

F=-50N

Explanation:

as per newton's second law of motion,

F=ma

m=100kg

a=(final velocity - initial velocity)/time

a=(0-5)/0.1

a=-0.5

F=100*(-0.5)

F=-50N

negative sign indicates that the vehicle is decelerating,

Answer 2

Answer:

500 N

Explanation:

A vehicle mass of 10kg is moving with a velocity of 5ms. To stop it in 1/10th sec the required force in opposite direction is ​

Initial Velocity  = 5 m/s

Final Velocity = 0 m/s

Time = 1/10  sec

Using V = U + at

=> 0 = 5 + a(1/10)

=> a = -50 m/s²

Force Required in opposite direction = -ma

= -10 *(-50)

= 500 N

required force in opposite direction is ​ = 500 N