Question

A vehicle of 100 kg is moving with a velocity of 5m/S. To stop it in 1/10 s. The required force in opposite direction is

Answer 1

$use \: f = \frac{m(v - u)}{t} \\ f = \frac{100(0 - 5)}{0.1} \\ f = - 5000n$
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Answer 2

The mass of the vehicle [m] = 100 kg

The initial velocity [u] = 5 m/s.

The time required to stop the vehicle [t[ = 1/10 s i.e 0.1 second.

The final velocity of the vehicle [v] = 0 m/s.

As per Newton's second law of motion, we know that force is equal to rate of change of momentum. Mathematically it can be written as -

                                                     $F=\frac{dp}{dt}$

Here F and p stands for force and momentum.

                                                             $=\ m\frac{v-u}{t}$

                                                             $=\ 100\frac{[0-5]}{0.1} \ N$

                                                             $=\ -5000\ N$  [ANS]

Negative sign is due to the fact that force is opposite to the displacement.