Question

A vehicle of 100 kg is moving with a velocity of 5m/S. To stop it in 1/10 s. The required force in opposite direction is

Answer 1

m = 100 kg
u = 5 m/s
v = 0
t = 0.1 s

Now

a = v-u / t
= -50 metre per second square


Now,

Force = ma
= 100 × -50
= -5000 N

The required force in opposite direction is 5000 N

Answer 2

Answer:

500 N

Explanation:

A vehicle mass of 10kg is moving with a velocity of 5ms. To stop it in 1/10th sec the required force in opposite direction is ​

Initial Velocity  = 5 m/s

Final Velocity = 0 m/s

Time = 1/10  sec

Using V = U + at

=> 0 = 5 + a(1/10)

=> a = -50 m/s²

Force Required in opposite direction = -ma

= -10 *(-50)

= 500 N

required force in opposite direction is ​ = 500 N