Question

A vehicle of mass 1000 kg is moving with a velocity of 15m/s it is brought to rest by brakes if frictional force is 6000n distance moved before coming to rest

Answer 1

$\displaystyle{\Huge{\underline{\underline{\mathfrak{Answer \colon}}}}}$

From the Question,

• Mass of the Particle,m = 1000 Kg

• Frictional Force,f = 6000 N

• Initial Velocity,u = 15 m/s

As,the object comes to rest due to friction

• Final Velocity,v = 0 m/s

Using the Relation,

$\huge{ \boxed{ \boxed{ \green{ \sf{f = ma}}}}}$

Putting the values,we get :

$\implies \: \sf{6000 = 1000a} \\ \\ \implies \: \sf{a = \frac{6 \cancel{000}}{ \cancel{1000}} } \\ \\ \implies { \huge{ \mathtt{ \: a = {6 \: ms}^{ - 2} }}}$

From

$\huge{ \boxed{ \boxed{ \green{ \sf{v {}^{2} = u {}^{2} - 2as}}}}}$

Putting the values,we get :

$\implies \: \sf{0 {}^{2} = 15 {}^{2} + 2(6)s } \\ \\ \implies \: \sf{12s \: = - 225} \\ \\ \implies \: \huge{ \mathtt{s = - 18.75m}}$

Here,

The negative sign indicates distance covered towards negative x - axis due to the frictional force