Question

a vehicle of mass 1000 kg moving with a velocity of 20 m/s is brought to rest in 5 seconds after covering a distance of 50m. find acceleration .calculate the unbalanced force acting on a vehicle

Answer 1

v^2-u^2=2as 20^2-0=2×a×50. 20×20÷50×2=a
a =4m/s^2. F=ma=1000×4=4000N.

Answer 2

V^2 - U^2= 2as. [ 3rd eq.]

=>(20)^2 - (0)^2 =(2)(a)(50)

=>400 - 0 = 2a × 50

=> 2a × 50 = 400

=> 2a = 400/50

=> 2a = 8

=> a = 8/2

=> a = 4 m/s^2....... (i)

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F=ma

▪F = -1000 × 4 N

¤ F = -4000 N.

HOPE IT HELPS..