A Vehicle of mass 120 kg is moving with a velocity of 90 kmph find the magnitude of force that is to be applied on the vehicle to stop in 5s
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Answered by
6
f=m( v-u)/t by this formula we get
f=120(25-0)/5=-600 N
f=120(25-0)/5=-600 N
Answered by
2
Since Impulse=Change in momentum
F.∆t=mv
F×5=(120×90×5)/18
F=600N
Did×5/18 to convert into m/s from km/h.
Hope you got it.....!!
F.∆t=mv
F×5=(120×90×5)/18
F=600N
Did×5/18 to convert into m/s from km/h.
Hope you got it.....!!
Baazigar:
Mark me as brainliest, if mine was more clear than previous answer.
ok
when the question can be solved through simple law of motion equation then what is the use of using such uncommon equations like the impulse equation
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