a vehicle starting from rest attains a speed of 72 km/h after covering a distance of 100m. if the mass of the vehicle is 500 kg, find the force exerted by the engine?
Answers
Answered by
30
72 kmph = 72 × 5/18 m/s = 20 m/s
a = (v² - u²) / (2S)
= [(20 m/s)² - 0] / (2 × 100 m)
= 2 m/s²
F = ma
= 500 kg × 2 m/s²
= 1000 N
= 1 kN
Force exerted by engine is 1 kN
a = (v² - u²) / (2S)
= [(20 m/s)² - 0] / (2 × 100 m)
= 2 m/s²
F = ma
= 500 kg × 2 m/s²
= 1000 N
= 1 kN
Force exerted by engine is 1 kN
Similar questions