Math, asked by Rabie3142, 1 year ago

A vendor bought some bananas at 4 per rupee and an equal number at 5 per rupee. when he sold the entire quantity at 9 for 2 rupees. What is his percentage profit or loss?
A) No profit, no loss
B) 8.88% profit
C) 6.66% loss
D) 1.23% loss

Answers

Answered by dikshaagarwal4442
1

Answer:

The correct option is: D) 1.23% loss

Step-by-step explanation:

  • Step-1: Suppose the vendor bought 'x' bananas at 4 per rupee.

       Price of 'x' bananas =Rs. \frac{x}{4}

       He should bought 'x' bananas at 5 per rupee.

        Price of 'x' bananas =Rs. \frac{x}{5}

        The vendor bought total 2x bananas wit Rs. \frac{x}{4} + \frac{x}{5} =Rs. \frac{9x}{20}  

  • Step-2: He sold those 2x bananas at a rate of 9 bananas per 2 rupees. The selling price of 2x bananas =Rs. \frac{4x}{9}

                      The cost price of 2x bananas = Rs. \frac{9x}{20}  

                      The profit = selling price - cost price = \frac{4x}{9} - \frac{9x}{20} = - \frac{x}{180}

   Negative profit indicates loss. The loss amount = Rs.\frac{x}{180}

   Percentage of loss = \frac{loss}{cost price} \times100% = \frac{\frac{x}{180} }{\frac{9x}{20} } \times 100% = 1.23%

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