Math, asked by pgrover961, 10 months ago

A vendor buys bananas at 19 for Rs 18 and sells at 18 for Rs 19. What will be the profit or loss (in %)?

Answers

Answered by sujitsinghbgs
0

Answer:

vendor buy bananas 19 for 18 and sells at 18 for rs 19

Step-by-step explanation:

vendor loss 10%

Answered by payalchatterje
0

Answer:

Profit percentage will be 11.419%.

Step-by-step explanation:

Given vendor buys bananas at 19 for Rs 18

So cost price of 1 banana is

rupees \:  \frac{18}{19}

(By unitary method )

He sells that bananas at 18 for Rs 19

So, selling price of 1 banana is

rupees \:  \frac{19}{18}

We know,

cost \: price = 100\% \\  \frac{18}{19 }  = 100\% \\ 1 =  \frac{100}{ \frac{18}{19} }   = 100 \times  \frac{19}{18}  \\  \frac{19}{18}  = 100 \times  \frac{19}{18}  \times  \frac{19}{18}  = 111.419 \%

[By unitary method ]

Profit percentage is (111.419-100)%=11.419%

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