Question

a verandah 2m wide is constructed all around a room of dimensions 8m *5m find the area of the verandah?

Answer 1

hiii!!!

here's ur answer...

$given \: length \: of \: the \: room \: is \: 8m \: and \\ breadth \: of \: the \: room \: is \: 5m. \\ \\ hence \: area \: of \: the \: room = l \times b \\ = 8 \times 5 \\ = 40 {m}^{2} \\ \\ if \: the \: verandah \: is \: 2m \: wide \: constructed \: \\ all \: around \: the \: room \: then \: the \: length \: of \\ the \: verandah \: will \: be = 8 + 2 + 2 \\ = 8 + 4 \\ = 12m \\ \\ and \: breadth \: of \: the \: room \: will \: be \\ = 5 + 2 + 2 \\ = 5 + 4 \\ = 9m \\ \\ hence \: area \: of \: the \: room \: along \: with \: the \\ verandah \: is = l\times b \\ = 12 \times 9 \\ = 108 {m}^{2} \\ \\ therefore \: area \: of \: the \: verandah \\ = 108 - 40 \\ = 68 {m}^{2} \\ \\ hope \: this \: helps.....$

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Answer 2

Answer:

length of outer rectangle=8+2+2+12m

breadth of outer rectangle=5+2+2=9m

area of outer rectangle=l×b=12×9=108m^2

length of inner rectangle =8m

breadth of inner rectangle=5m

area of inner rectangle=l×b=8×5=40m^2

there fore area of verandha=(area of outer figure )-(area of inner figure)

=108-40=68m^2....

hope this helped you........