Math, asked by attitudegirl80, 10 months ago

A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:
(i) the area of the verandah.
(ii) the cost of cementing the floor of the verandah at the rate of ₹ 200 per m2.

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Answers

Answered by xItzKhushix
12

\huge\mathfrak{\underline{Correct\:question}}

A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:

(i) the area of the verandah.

(i) the area of the verandah.(ii) the cost of cementing the floor of the verandah at the rate of ₹ 200 per m^2

______________________________

Given that:-

  • A verandah of width 2.25 m is constructed all along outside a room

  • Length of room = 5.5m

  • Width of room = 4m

To find:-

  • Area of verandah

  • The cost of cementing the floor of the verandah at the rate of ₹ 200 per m^2

Answer:-

\bold{STEP-BY-STEP-EXPLANATION}

From the question it is given that,

Length of the room (L) = 5.5 m

Breadth of the room (B) = 4 m

Then,

Area of the room = length × breadth

= 5.5 × 4

= 22 m^2

From the figure,

The new length and breadth of the room when verandah is included is 10 m and 8.5 m respectively.

New area of the room when verandah is included =

10 × 8.5

= 85 m^2

The area of verandah = Area of the room when verandah is included – Area of the room

= 85 – 22

= 63 m^2

(ii) Given, the cost of cementing the floor of the verandah at the rate of ₹ 200 per m^2

Then the cost of cementing the 63 m^2 area of floor of the verandah

= 200 × 63

= ₹ 12600

Therefore, area of verandah = 63m^2 and cost of cementing the floor = ₹ 12600.

#BAL

#AnswerWithQuality

Attachments:
Answered by cubingwitskm
7

Answer:- 63cm^2

12600 rupees

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