Question

A verandah of width 3 m is constructed along the outside of a room of length 9 m and width 7 m. Find (a) the area of the verandah (b) the cost of cementing the floor of the verandah at the rate of ₹15 per sq.m.​

Answer 1

Step-by-step explanation:

Given: Length of room =5.5m,

Width of room =4m,

Width of verandah which is constructed all along outside of room =2.25m,

Cost of cementing of verandha = Rs 200 per sq.m

∴, Length of room with verandah=5.5+2.25+2.25=10m

Width of room with verandah=4+2.25+2.25=8.5m

Area of room=Length×Width=5.5×4=22m

2

Area of room with verandah= Length×Width=10×8.5=85m

2

Area of verandah=Area of room with verandah−Area of room=85−22=63m

2

Cost of cementing of verandah=Area×Rate=63×Rs.200=Rs.12600

Answer 2

Answer:

(a) 27 m^2

(b) ₹405

Step-by-step explanation:

(a) length= 9m

width= 3m

Area= length x width

       = 9 x 3

       = 27 m^2

(b) Cost= 27 x 15

            = ₹405