Physics, asked by d85difzrjzrff, 11 months ago

a vernier callipar has 20 division on vernier scale . 1cm on the main scale is divided into 20 equal parts . find least count with process

Answers

Answered by scooter1282005
1

Rjofspecoyqpg1 Ambitious

VSD - Vernier scale divisions.   MSD - Main scale divisions.  


Given that 20 VSD = 19 MSD

Then 1 VSD = (19)/(20) MSD= 0.95 MSD.


Least count of Vernier calipers, LC  = 1 MSD -1 VSD

           = 1 MSD - 0.95 MSD = 0.05 MSD.

As 1 MSD = 2mm,  

Least count, LC = 0.05 x 2 mm = 0.1 mm.




d85difzrjzrff: i dont know in my book answer is 0.25
d85difzrjzrff: it ok thanks for your help
d85difzrjzrff: it ok bye
d85difzrjzrff: because this time for my study
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