A vernier has 10 divisions and they are equal to 9 divisions of main scale in length. if the main scale is calibrated in mm,what is its least count?
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76
Value of one MSD (Main Scale Division) = 1/10
Hence,the least count = (Value of 1 MSD)/No. of divisions on the vernier scale
= 0.01
Hence,the least count = (Value of 1 MSD)/No. of divisions on the vernier scale
= 0.01
Answered by
6
Answer:
Explanation: 1mm
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