a vertical extension in light spring by 1kg weight of 1kg in equilibrium is 9.8 cm.. the period of oscillation of the spring is
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Answer:
2pi/10 sec
Explanation:
mg=kx, m/k=x/g
T=2pi(m/k)½=2pi(x/g)½
T=2pi(9.8×10^-2/9.8)½=2pi/10 sec
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