Question

a vertical lenght of 6m cast a shadow 400cm long on the ground and at the same time a tower casts a shadow 28m long .using similarity,find the height of the tower.

Answer 1

Given:-

• Length of vertical pole = 6m

• Shadow of pole = 4m

• Length of shadow of tower = 28m

To find:-

• Height of tower

Solution:-

Let height of tower be h m

★ In ∆ABC and ∆DEF,

∠C = ∠E [Angular elevation of sum]

∠B = ∠F = 90°

∆ABC ∼ ∆DEF (∵ By AA similarity criterion)

$\dashrightarrow\sf \dfrac{AB}{DF} = \dfrac{BC}{EF}$ (∵ If two triangles are similar their corresponding sides)

$\dashrightarrow\sf \dfrac{6}{h} = \dfrac{4}{28}$

$\dashrightarrow\sf h = 6 \times \dfrac{ \cancel{28}}{ \cancel{4}}$

$\dashrightarrow$ h = 6 × 7

$\dashrightarrow$ h = 42m

Therefore, Height of tower is 42m.

$\rule{200}3$

Answer 2

hope it's helpful for u...

thnx