Find the discriminant of √3x2 +2√2x -2√3 =0
a. 22
b. 32
c. 12
d. 2
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2
Answer:
√2-4√3
Step-by-step explanation:
On comparing the values, we get,
a = √3
b = 2√2
c = -2√3
D = (-b + 4ac)/2
D = {-2√2 + 4 (√3×-2√3)/2
D = (-2√2 + 4√3-8√3)/2
D = (-2√2 -4√3)/2
D = √2(√2-2√3)/2
D = √2-4√3
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