Question

A vertical pole of 10m casts a shadow of 8 meters at a certain time of the day. The length of the shadow cast by a tower standing next to the pole of height 110 m is

Answer 1

Answer:

88 meters.

Step-by-step explanation:

Given that a vertical pole with a height of 10 meters, casts a shadow of 8 meters at a certain time of the day.

Let us assume that the inclination of the sun at that time of the day is α.  

So, we can write tanα=10/8=1.25, ⇒α= tan¬1(1.25)=51.34°

Now, a tower is standing next to the pole with a height 110 meters and assume that it cast x meters of shadow at the same time of the day.

Then, it can be written that  

tanα= tan(51.34°)=1.25=$\frac{110}{x}$

⇒ x= 110/1.25=88 meters.

Therefore, the tower will cast 88 meters long shadow on the ground.  

(Answer)