A cubical block of side 10cm is surmounted by a hemisphere what is the largest diameter that the hemisphere can have find the cost of painting the total surface area of the solid so formed at the rate of 5 per 100sqcm
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Answer:
rs 33.93
Step-by-step explanation:
The greatest diameter the hemisphere can have i 10cm
T.S.A of the solid = surface area of the cube +CSA of the hemisphere - area of the base of the hemisphere
=6×102+2×227×5×5−227×5×5
=600+227×25
=600+78.57
=678.57cm2
∴ Cost of printing the block at the rate of Rs5/100 square is
100sq.cm=5
678.57=?
67.57100×5=33.93
Hence the amount is Rs.33.93
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