Question

A vertical pole of 10m casts a shadow of 8m at certain times of the day the length of shadow cast by a tower standing next to the pole of heights of 110m is​

Answer 1

Answer:

The answer is 128 m.

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Answer 2

Let the height of the pole be AB = 10 m and the length of its shadow be BC = 8 m.

Let the height of the tower be PQ = 110 m and the length of its shadow be QR = x.

Thus, Δ ABC and Δ PQR are equiangular.

Hence, the length of the shadow cast by the tower is 88 m.