a vertical pole of 5.6 metre high Casts a shadow 3.2 M long at the same time find 1. the length of the shadow cast by another ball 10.5 m high 2. the height of a pole which casts a shadow 5m long
Answers
Answer:
Step-by-step explanation:
1) Let,
CD = pole = 5.6m
AB = Ball. = 10.5m
DE = Shadow of pole = 3.2m
BE = Shadow of ball = ?
Solution:-
In ∆ABE and ∆CDE
angleABE = angleCDE (Each90°)
angleAEB = angle CED(common)
By AA similarity,
∆ABE ~ ∆CDE
Therefore, AB/CD=BE/DE
10.5/5.6=BE/3.2
BE=10.5/5.6 *3.2
BE=105/7*4
BE=15*4
BE=60m
2) Let,.
AB=pole• casting Shadow 5m=?
CD =pole =5.6m
BE = Shadow of pole• =5m
DE = Shadow of pole = 3.2m
Solution:-
∆ABE ~ ∆CDE. (AA similarity)
Therefore, AB/CD=BE/DE
AB/5.6=5/3.2
AB=5*5.6/3.2
AB=5*7/4
AB=35/4
AB=8.75 m
Shadow of ball is 60m,and height of pole•is 8.75m
Answer:
Step-by-step explanation:
1) Let,
CD = pole = 5.6m
AB = Ball. = 10.5m
DE = Shadow of pole = 3.2m
BE = Shadow of ball = ?
Solution:-
In ∆ABE and ∆CDE
angleABE = angleCDE (Each90°)
angleAEB = angle CED(common)
By AA similarity,
∆ABE ~ ∆CDE
Therefore, AB/CD=BE/DE
10.5/5.6=BE/3.2
BE=10.5/5.6 *3.2
BE=105/7*4
BE=15*4
BE=60m
2) Let,.
AB=pole• casting Shadow 5m=?
CD =pole =5.6m
BE = Shadow of pole• =5m
DE = Shadow of pole = 3.2m
Solution:-
∆ABE ~ ∆CDE. (AA similarity)
Therefore, AB/CD=BE/DE
AB/5.6=5/3.2
AB=5*5.6/3.2
AB=5*7/4
AB=35/4
AB=8.75 m
Shadow of ball is 60m,and height of pole•is 8.75m