a vertical pole of length 6m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long. find the height of the tower.
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Given,
Length of the vertical pole = 6 m
Shadow of the pole = 4 m
Let the height of the tower be h m.
Length of the shadow of the tower = 28 m
Class 10 Maths Chapter 6 Triangles 04
In ΔABC and ΔDFE,
∠C = ∠E (angle of elevation)
∠B = ∠F = 90°
By AA similarity criterion,
ΔABC ~ ΔDFE
We know that the corresponding sides of two similar triangles are proportional.
AB/DF = BC/EF
6/h = 4/28
h = (6 ×28)/4
h = 6 × 7
h = 42
Hence, the height of the tower = 42 m
Hope it's Helpful....:)
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