a vertical pole of length 8m casts a shadow of 15 m long on the ground. at the same time a tower casts a shadow of 45 m long. find the height of the tower
Answers
Answer:
The height of tower = 24m.
Step-by-step explanation:
//Vertical pole
Length of pole = 8m.
length of shadow = 15m.
//Imagine a right angled triangle with h = 8m and base = 15m . now to get hypotenuse use Pythagoras theorem
let z be the hypotenuse
z² = 8² + 15²
z = 17m.
Sinθ = opposite side to θ /hypotenuse = 8/17.
//now calculate for tower.
let x be the height of tower
length of shadow = 45m
//Imagine a right angled triangle with h = xm and base = 45m . now to get hypotenuse use Pythagoras theorem
let w be the hypotenuse.
w² = x² + 45²
w = √(x² + 45²)
Sinθ = opposite side to θ /hypotenuse = x/√(x² + 45²)
//since the angle of sun be will be same.
8/17 = x/√(x² + 45²)
//square on both sides
64/289 = x²/x² + 45²
=> 289x² = 64x² + 45²*64
=> 225x² = 45²*64
= x² = 45²*64/225 = 576.
=> x = 24m.
The height of tower = 24m.
Answer:
- i hope you like my answer please mark as brainlist
