A vertical stick 1.2m long casts shadow 40cm long on the ground. At the same time a pole 6m high casts a shadow x on the ground. The value of x is
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In △ABC and △DEF
∠A=∠D=90∘
Since the tower and the stick cast their respective shadows at the same time on the ground,
So, ∠C=∠F
∴△ABC∼△DEF ....(by AA similarity)
DEAB=DFAC⇒x12=408
⇒x=60 m
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