A vertical stick 10 cm long casts a shadow 8 cm long At the same time a tower casts a shadow 30 m long Determine the height of the tower
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We have to find the length of AB(refer the enclosed attachment).
In ∆PQR,
tan theta=10/8=5/4----------(1)
In ∆ABC,
tan theta=AB/30-----------(2)
Using equations (1) and (2),
↪5/4=AB/30
↪AB=5×30/4
↪AB=150/4
↪AB=37.5
➡Thus, the height of the tower, AB=37.5 m.
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