Question

a vertical stick 20 cm long casths a shadow 10 cm long on the ground. at the same time, a tower casts a shadow 50 m long on the ground. the height of the tower is​

Answer 1

Answer:

In ΔABC & ΔADE

∠BCA=∠DEA=90

o

[Each are at 90

o

to the ground]

∠BAC=∠DAE [common angle]

∠CBA=∠EDA [∵ the sum will cast light a equal angles]

Hence, by AAA, ΔABC∼ΔADE

⇒

CA

BC

=

EA

DE

⇒

10

20

=

50

DE

⇒DE=100

∴ The height of the tower is 100m.

solution

Step-by-step explanation:

the pic is edited but don't worry it is not written any thing there it's just a triangle.

Answer 2

Answer:

100 m

Step-by-step explanation:

Shadow = 1/2 Height

50 m = 1/2 Height

or, 2 x 50 = Height

or, 100 m = Height