Question

A vertical stick of length 6 m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long . Then the height of the tower is

Answer 1

Step-by-step explanation:

Height of pole=AB=6 m

Length of shadow of pole =BC=4 m

Length of shadow of tower=EF=28 m

In △ABC and △DEF

∠B=∠E=90∘ both 90∘ as both are vertical to ground

∠C=∠F  (same elevation in both the cases as both shadows are cast at the same time)

∴△ABC∼△DEF by AA similarity criterion

We know that if two triangles are similar, ratio of their sides are in proportion

So,DEAB=EFBC

⇒DE6=284

⇒DE=6×7=42 m

Hence the height of the tower is 42 m

Answer 2

Answer:

The Height is 42 m...........