Question

A vertical tower stands on a horizontal plain and has a vertical flag of height 6meter on it's top. At a point from the ground, the angle of elevation of bottom and top of the flag are 30degree and 45degree. Find the height of the tower.


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Answer 1

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Let BC be the height of the tower and DC be the height of the flag - staff.

In rt.△ABC,

AB = BC cot 30°

AB = BC √3......(i)

In rt.△ABD,

AB = BD cot 45°

AB = (BC + CD) cot 45°

AB = (BC + 7).......(ii)

Equating (i) and (ii)

(BC + 7) = BC √3

BC(√3-1) = 7

BC = 7/0.73 = 9.58 m

Therefore the height of the tower is 9.58 m.

Answer 2

Answer:

The height of the tower is 9.58

m

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