Question

A vertical tree is Broken by a wind the Height of 6m from
its foot its top touches the Ground at the distance of
o m from the foot of the thee calculate the distance between
the top of the the before breaking and the point at
which the see touches the Ground after break.​

Answer 1

Answer:

12 m

Step-by-step explanation:

if after breaking, the distance between top and base of tree is 0m. Then it means it broke in half. So, the the height of tree before breaking is 12m.

Answer 2

The distance between the top and the point where the tree touches the ground=$8\sqrt 5$m

Step-by-step explanation:

Let x be the length of broken part.

Total height of tree=x+6 m

Distance between foot of tree and the point where the tree touch the ground=8 m

In triangle BCD

$BD^2=BC^2+CD^2$

Using Pythagoras theorem

$(Hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2$

$x^2=6^2+8^2=36+64=100$

$x=\sqrt{100}=10 m$

Total height of tree=x+6=10+6=16 m

In triangle ACD

$AD^2=AC^2+CD^2$

Substitute the values

$AD^2=(16)^2+8^2$

$AD^2=256+64$

$AD^2=320$

$AD=\sqrt{320}=8\sqrt 5$m

Hence, the distance between the top and the point where the tree touches the ground=$8\sqrt 5$m

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