Question

a verticall steel post of diameter 25cm and length 2.5m support a weight of 8000kg find change in length produced if Y=2×10^11 pa​

Answer 1

Answer:

Explanation:

F/A=Y(ΔL/L)

ΔL=FL/YA

ΔL=(mg)L/Y(πD²/4)

ΔL=(8000×10)×2.5/2×10^11(π25×25×10^-4/4)

ΔL=2.1×10^-5

ΔL=8000×10