Math, asked by ayushgathe6211, 1 year ago

A vertically straight tree 15m high is broken by the wind in such a way that its top just touches the ground and makes an angle of 60 degree. At what height from the ground did the tree break ?

Answers

Answered by pinquancaro
198

Answer:

The height above the ground from the tree broke is 6.9 meter.

Step-by-step explanation:

Given : A vertically straight tree 15m high is broken by the wind in such a way that its top just touches the ground and makes an angle of 60 degree.

To find : At what height from the ground did the tree break ?

Solution :

The height of the tree = 15 m

Refer the attached figure below.

Suppose it broke at 'C' and its top 'A' touches the ground at 'D'

Now, AC = CD, and angle BDC = 60°

Let BC = 'x'

So, AC = 15 - x and CD = 15 - x

In right angle BCD,

\frac{BC}{CD}=\sin 60^\circ

\frac{x}{15-x}=\frac{\sqrt3}{2}

2x=(15-x)\sqrt3

2x=15\sqrt3-\sqrt3 x

2x+\sqrt3 x=15\sqrt3

x(2+\sqrt3)=15\sqrt3

x=\frac{15\sqrt3}{(2+\sqrt3)}

x=\frac{25.98}{3.73}

x=6.96

Therefore, The height above the ground from the tree broke is 6.9 meter.

Attachments:
Answered by marefath123
119

hope this will help u

follow me for more help guys!☺️☺️☺️☺️

Attachments:
Similar questions