Question

A vertically straight tree,15m high,is broken by the wind in such a way that its top just touched the ground and makes the angle of 60 degree with the ground.At what height from the ground did the tree break?​

Answer 1

Answer:

Initially the Height of the Tree =15 m

Now , when it breaks a part of it will remain Perpendicular to the Ground (AB) and remaining part (AD) will make angle of 60

o

or we can say AB+AD=15 m.............(1)

Now, in △ABD

sin60

o

=

AD

AB

⇒AB=

2

3

AD

.............(2)

From (1) and (2)

AD

2

3

+1

=15 m

⇒AD=

3

+1

30

=10.98 m (Take

3

=1.73)

From (1)

AB+10.98=15⇒AB=4.02 m

So its broken at 4.02 m from ground