Question

A verticle pole of the length is6m casts a shadow 4m long on the ground and at the same time a towercasts a shadow28m long find the height of the tower

Answer 1

Let height of tower be x

The tan∆for pole will be perpendicular divided by base

It will be 6divided by4

And then

Tan ∆for tower will also be perpendicular divided by base

It will be x divided by 28

Putting both equally as both are of same time so there angle(∆) will be same

So

6 Divided by 4=x divided by 28

X =42

Height of tower will be 42m