A very broad elevator is going up vertically with the constant acceleration 1 m per second square at the instant when the velocity of the lift is 2m per second a stone is projected from a floor of the left his feet to metre per second related floor at an elevation 30 degree find
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omponent of velocity of ball relative to lift are
ux=4cos30∘=23–√m/sux=4cos30∘=23m/s
uy=4sin30∘=2m/suy=4sin30∘=2m/s
and acceleration of ball relative to lift is a=10+2=12m/s2a=10+2=12m/s2 in negative y direction acting downwards.
Therefore Time of flight T=2uyaT=2uya
=2×212=2×212
=13s=13s
Hence b is the correct answer.
ux=4cos30∘=23–√m/sux=4cos30∘=23m/s
uy=4sin30∘=2m/suy=4sin30∘=2m/s
and acceleration of ball relative to lift is a=10+2=12m/s2a=10+2=12m/s2 in negative y direction acting downwards.
Therefore Time of flight T=2uyaT=2uya
=2×212=2×212
=13s=13s
Hence b is the correct answer.
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