Question

A vessel contains 20 % concentrated solution of Sulphuric acid. If 50 ml more sulphuric acid is added in it, then concentration of Sulphuric acid in vessel becomes 36 % What is the volume of sulphuric acid in original mixture in vessel?


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Answer 1

Answer:

Volume of Sulphuric acid in original mixture = 40 ml

Step-by-step explanation:

Vessel contains 20% Concentrated Solution of Sulphuric acid

Let say total solution = 100 S  ml

Sulphuric acid = (20/100)100S = 20S ml

50 ml more sulphuric acid added

now Sulphuric acid = 20S + 50 ml

Total Solution = 100S + 50 ml

now sulphuric acid = 36%

(36/100)(100S + 50) = 20S + 50

36S + 18 = 20S + 50

16S = 32

S = 2

Slphuric acid = 20S = 20*2 = 40 ml

Volume of Sulphuric acid in original mixture = 40 ml

Answer 2

40 ml is your answer