Question

A vessel contains a mixture of nitrogen of mass 7g and carbon dioxide of mass 11 g at temperature 290 k and pressure 1 atm. find the density of the mixture

Answer 1

here is your answer buddy

Answer 2

Answer : The density of the mixture is, 1.512 g/L

Solution : Given,

Mass of nitrogen gas = 7 g

Mass of carbon dioxide gas = 11 g

Molar mass of nitrogen gas = 28 g/mole

Molar mass of carbon dioxide gas= 44 g/mole

First we have to calculate the total number of moles of the mixture.

$n_{total}=n_{N_2}+n_{CO_2}\\\\n_{total}=\frac{7g}{28g/mole}+\frac{11g}{44g/mole}=0.5moles$

Now we have to calculate the total volume of the mixture.

using ideal gas equation,

$PV_{total}=n_{total}RT\\\\V_{total}=\frac{n_{total}RT}{P}$

where,

P = pressure of mixture of gas = 1 atm

T = temperature of mixture of gas = 290 K

R = gas constant = 0.0821 Latm/moleK

Now put all the given values in the ideal gas equation, we get

$V_{total}=\frac{(0.5moles)\times (0.0821Latm/moleK)\times (290K)}{1atm}=11.9045L$

Now we have to calculate the density of the mixture.

$Desnity=\frac{Mass}{Volume}=\frac{(7+11)g}{11.9045L}=\frac{18g}{11.9045L}=1.512g/L$

Therefore, the density of the mixture is, 1.512 g/L