Math, asked by ds9766162gmailcom, 1 day ago

A vessel contains mixture of Milk & water from which 40% of mixture from vessel is replaced with mango juice. Resulting quantity of water in vessel is 25% more than milk, while resulting quantity of mango juice in vessel is 50% more than milk. If initial quantity of milk in vessel is 10 liters less than water and X% of resulting mixture taken out, then sum of water & mango juice in vessel becomes 33 liters. Find ​

Answers

Answered by chandranravi39783
0

Answer:

22litre

Step-by-step explanation:

Because

the water has been

reduced to the heat of the pressure in a

vessel

how it is useful

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Answered by ravilaccs
0

Answer:

The added quantity of the water is 30 litres.

Step-by-step explanation:

So, in the given numerical, the % of pure milk in the mixture is 40%. That means that the quantity of water is 60%. For making the ratio of milk and water 1:1, there is no need of changing the percentage of water. The % of water will remain the same. To make the ratio 1:1, you simply need to add 20% pure milk to the mixture.

So, quantity of pure milk to be added = 20 % of 25 litres

= 0.2 x 25 litres

= 5 Litres.

So, 5 Litres of pure milk will needed to be added so as to make the ratio 1:1

The total quantity of mixture = 60 liters Percentage of water in the mixture = 10% Calculation: Let the added quantity of water be x According to the question, we have, The quantity of water in the original mixture, ⇒ 60 × 10% ⇒ 60 × (10/100) ⇒ 6 liters After adding x liters of water, the new quantity of water = x + 6 And the total quantity of mixture will become = x + 60 According to the question, New amount of water in the mixture is 40% So, {(x + 6)/(x + 60)} × 100 = 40 ⇒ {(x + 6)/(x + 60)} = 2/5 ⇒ 5x + 30 = 2x + 120 ⇒ 3x = 90 ⇒ x = 30 litres ∴ The added quantity of the water is 30 litres.

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