Question

A vessel contains oil (density 0.8 g/cm cube) over mercury (density 13.6 g /cm cube ) . A homogenous sphere floats with half volume immerser in mercury and the other half in oip . The density of the material of the sphere is

Answer 1

mg = density of oil g V/2+ density of mercury g V/2

mg = 8000 v/2 + 136000 V/2

m = 800 v/2 + 13600V/2

m = 400 v + 6800 V

m/v = 7200 kg/m^3 = 7.2 g/cm^3

Answer 2

The density of the material of the sphere is 7.2 $\dfrac{g}{cm^3}$.

Explanation:

Given,

The density of oil, $\rho_{o} =0.8\dfrac{g}{cm^3}$ and

The density of mercury, $\rho_{m} =13.6\dfrac{g}{cm^3}$

To find, the density of the material of the sphere = ?

∴ The density of the material of the sphere $=\dfrac{\rho_{o}+\rho_{m}}{2}$

$=\dfrac{0.8+13.6}{2}$

$=\dfrac{14.4}{2}$

= 7.2 $\dfrac{g}{cm^3}$

Hence, the density of the material of the sphere is 7.2 $\dfrac{g}{cm^3}$.