A vessel contains water up to a height of 20 cm and above it an oil up to another 20 cm. The refractive indices of the water and the oil are 1.33 and 1.30 respectively. Find the apparent depth of the vessel when viewed from above.
Answers
The apparent depth of the vessel when viewed from above is 30.42 cm
Given, the refractive index of water is μ = 1.33, and depth of water, d = 20cm
So, shift due to water, t = (1 - 1/μ)*d
Substituting the values, we get t as,
t = (1 - 1/1.33)*20
= 4.96 cm
Again, the refractive index of oil is μ' = 1.30, and depth of oil, d' = 20cm
So, shift due to water, t' = (1 - 1/μ')*d'
Substituting the values, we get t' as,
t' = (1 - 1/1.30)*20
= 4.62 cm
Total shift = t + t' = 4.96cm + 4.62 cm
= 9.58cm
Total height = 20 cm + 20cm = 40cm
Thus, apparent depth = 40cm - 9.58cm
= 30.42 cm
This is the required answer.
The apparent depth of the vessel when viewed from above is 30.4 cm.
Explanation:
To find the apparent depth of the vessel :
Step 1:
Given data :
Water and oil refractive indices: 1.33 and 1.30
Water height =20 cm
Oil height = 20 cm
Step 2:
Move due to water
= 0.248×20
= 4.96 ≈ 5cm
Step 3:
Shift due to oil :
= 20- 15.3
= 4.6 cm
Total Change = 5 + 4.6 = 9.6 cm
Apparent depth = 40 - 9.6
= 30.4 cm.
Thus, the apparent depth of the vessel is 30.4 cm from the surface.