A vessel full of water is in the form of an inverted cone of height 16cm and the radius of its top,
which is open, is 10 cm. When 100 spherical lead balls are dropped into the vessel, one fourth of
the water flows out of the vessel. Find the radius of a spherical ball
. (n-).
Answers
Answered by
1
Answer:
HappiestWriter012
HappiestWriter012
We know that Volume of cone = πr²h/3
=π*5²*8/3
=200/3π
Now
volume of liquid displaced=volume of balls dropped
1/4(200/3)π=100*4/3πr³
50=100*4r³
50/4=100r³
50/400=r³
1/8=r³
r=1/2=0.5cm
hope helped!
Answered by
0
Step-by-step explanation:
Radius of cone =5cm
Height of cone =8cm
Radius of sphere=0.5cm
Volume of cone is,
=
3
1
πr
2
h
=
3
1
π×5
2
×8
=
3
200
πcm
3
Volume of lead shot =
3
4
πr
3
Volume of lead shot =
3
4
πr
3
=
3
4
π×0.5
3
=
6
1
πcm
3
∴ number of lead shots =
3
200
π×
4
1
÷
6
1
π
=
3
50π
×
π
6
=100
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