Question

Construct a ABC in which BC = 7 cm, B = 45 and AB + AC = 13 cm.​

Answer 1

Step-by-step explanation:

i Steps of Construction:

Step I : Draw BX¯¯¯¯¯¯¯¯.

Step II : Along BX¯¯¯¯¯¯¯¯, cut off a line segment BC = 7 cm.

Step III : At B, construct ∠CBY = 75°

Step IV : From BY¯¯¯¯¯¯¯¯, cut off BD = 13 cm (= AB + AC)

Step V : Join DC.

Step VI : Draw a perpendicular bisector of CD which meets BD at A.

Step VII: Join AC.

Answer 2

Step-by-step explanation:

Given that,

In ΔABC,

BC=7cm,∠B=750&AB+AC=13cm.

Required: To construct the triangle ABC.

Then,

Draw the base BC=7cm.

At the point B make an angle XBC=750.

Cut a line segment BD equal to AB+AC=13cm from the ray BX.

Join DC.

Make an ∠DCY=∠BDC.

lET CY intersect BX at A.

Hence,

ABC is the required triangle.

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