Question

A vessel is in the form of a hemispherical bowl mounted by a hollow cylinder. The diameter of the hemisphere is 14 cm and total height of the vessel is 13 cm. Find the inner surface area of the vessel

Answer 1

Answer:

The inner surface area of the vessel is 572 cm square.

Step-by-step explanation:

Surface area of the vessel is : 2 x 22/7 x 7 x 6 + 2 x 22/7 x 7 x 7

                                               =  264+308

                                               =  572

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Answer 2

Solution:

Given:

=> Diameter of hemisphere = Diameter of cylinder = 14 cm.

=> Radius of hemisphere = Radius of cylinder = 7 cm.

=> Height of cylinder = Total height - radius of hemisphere

=> 13 - 7 = 6 cm.

To Find:

=> Inner surface area of vessel.

Formula used:

=> Curved surface area of cylinder = 2πrh

=> Curved surface area of hemisphere = 2πr²

So,

Curved surface area of cylinder = 2πrh

$\sf{\implies 2\times \dfrac{22}{7} \times 7\times 6}$

$\sf{\implies 264\;cm^{2}}$

Now, Curved surface area of hemisphere = 2πr²

$\sf{\implies 2\times \dfrac{22}{7}\times 7\times 7}$

$\sf{\implies 308\;cm^{2}}$

∴ Inner surface area of vessel = Curved surface area of cylinder + curved surface area of hemisphere

=> 264 + 308

=> 572 cm²

So, the inner surface area of vessel = 572 cm²