Math, asked by vikaskumar98, 5 months ago

A vessel is in the form of an inverted cone. Its height is 8 cm and the radius of its top which is

open is 5 cm. It is filled with water upto the brim. When lead shots, each of which is a sphere of

radius 0.5 cm are dropped into the vessel, one fourth of the water flows out. Find the number of

shots dropped in the vessel.​

Answers

Answered by Anonymous
2

GIVEN:-

\small\sf\green{height \:(h)\:of\:conical\:vessel=8cm}

\small\sf\green{radius \: (r1) \: of \: conical \: vessel=5cm}

\small\sf\green{radius\:(r2)\:of\:lead\:shots=0.5cm}

⠀⠀

\small\sf\orange{let \: n \: of \: lead \: shots \: were \: dropped \: in \: the \: vessel}

⠀⠀⠀

\small\sf\pink{Volume\:of\:water\:spilled=Volume\:of\:dropped\:lead\:shots}

⠀⠀

\longrightarrow\large\sf\red{\frac{1}{4}  \times volume \: of \: cone = n \times  \frac{4}{3} {r2}^{2} }

\longrightarrow\large\sf\red{ \frac{1}{4}  \times  \frac{1}{3} π {r}^{2} h = n \times  \frac{4}{3} π {r2}^{3} }

\longrightarrow\large\sf\red{{r1}^{2} h = h \times 16 {r2}^{3}}

\longrightarrow\large\sf\red{{5}^{2}  \times 8 = n \times 16 \times  {(0.5)}^{3} }

\longrightarrow\large\sf\red{n =   \frac{25 \times 8}{16 \times  { ( \frac{1}{2}) }^{3} }}

\longrightarrow\large\sf\red{n=100}

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