Question

the radius and slant height of a conical vessel are 35 cm and 91 cm respectively what is its capacity in litre​

Answer 1

Answer:

85800 cm sq

Step-by-step explanation:

l sq. =  r sq + h sq

91 sq = 53 sq + h sq

8281 - 1225=h sq

sq root 7056= h

h = 84

v(cone) = 1/3 x 22/7 x r sq x h

= 1/3 x 22/7 x 35 x 35 x 84

= 22 x 5 x 35 x 28

= 85800 cm sq

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Answer 2

Answer:

The required capacity of the vessel is 107800 cm³

Step-by-step explanation:

Given :

Radius of a vessel, r = 35 cm

Slant height of a vessel, l = 91 cm

To find :

the capacity of the vessel

Solution :

Since radius and slant height are given, let's find the height of the cone.

We know,

\underline{\boxed{\bf l=\sqrt{r^2+h^2}}}

l=

r

2

+h

2

h² = l² - r²

h² = 91² - 35²

h² = 8281 - 1225

h² = 7056

h = √7056

h = 84 cm

Volume of a cone is given by,

\boxed{\tt V=\dfrac{1}{3} \pi r^2h}

V=

3

1

πr

2

h

\begin{gathered}\longrightarrow \sf V=\dfrac{1}{3} \times \dfrac{22}{7} \times 35 \times 35 \times 84 \ cm^3 \\\\ \longrightarrow \sf V=22 \times 5 \times 35 \times 28 cm^3 \\\\ \longrightarrow \sf V=107800 \ cm^3\end{gathered}

⟶V=

3

1

×

7

22

×35×35×84 cm

3

⟶V=22×5×35×28cm

3

⟶V=107800 cm

3

Hence, the capacity of the vessel is 107800 cm³ (or) 0.1078 m³